Cutoff marks for qualifying in JEE (Advanced) 2015

A Candidate has to satisfy the subject-wise cut-off as well as the aggregate cut-off to be included in a rank list. A student who has secured >=177 marks out of 504 (35% aggregate) will be eligible for common Rank list in JEE Advanced 2015. While this is 159 (31.5%) in OBC & 89 (17.5%)  in Sc & ST category respectively.

Besides, a candidate also has to pass subject wise cut-off criteria. And this is >=17 marks (10%) in P,C,M each (out of 168 marks in each P,C,M)  for common merit list while >=16 ( 9%) in OBC and >=9 (5%) in SC & ST category.


Tie-break rules for ranking: Candidate with higher aggregate marks will be assigned a better/higher rank (smaller number).
If two candidates have the same aggregate marks, then the candidate with higher marks in mathematics will be assigned a better / higher rank (smaller number).
If two candidates have the same aggregate marks and same marks in mathematics, then the candidate with higher marks in physics will be assigned a better / higher rank (smaller number).
If two candidates have the same aggregate marks and same marks in mathematics and physics, then both the candidates will be assigned the same rank.
Source : http://jeeadv.iitb.ac.in/cutoff-marks-qualifying-jee-advanced-2015